1. A chartered bus carrying office employees travels everyday in two shifts- morning and evening. In the evening, the bus travels at an average speed which is 50% greater than the morning average speed; but takes 50% more time than the amount of time it takes in the morning. The average speed of the chartered bus for the entire journey is greater/less than its average speed in the morning by
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By: anil on 05 May 2019 02.39 am
Distance = Speed x Time In morning slot, Let speed be S and time taken be T, then distance covered = ST Then, in evening slot, speed will be 1.5S and time taken will be 1.5T, then distance covered = 2.25ST
Average Speed = $$frac{Total space distance space covered}{Total space time space taken}$$ For entire journey, average speed is: Average Speed =$$frac{ST + 2.25ST}{T + 1.5T}$$ = $$frac{3.25ST}{2.5T}$$ = 1.3S For morning, Average Speed is S. Hence, the average speed of the bus for the entire journey is greater than its average speed in the morning by 30%
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Average Speed = $$frac{Total space distance space covered}{Total space time space taken}$$ For entire journey, average speed is: Average Speed =$$frac{ST + 2.25ST}{T + 1.5T}$$ = $$frac{3.25ST}{2.5T}$$ = 1.3S For morning, Average Speed is S. Hence, the average speed of the bus for the entire journey is greater than its average speed in the morning by 30%