1. The coordinates of a triangle ABC are A(1, 5), B(-2, 3), and C(0,-4); find the equation of the median AD? ·
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By: anil on 05 May 2019 02.38 am
Given that $$ riangle$$ABC Since AD is the median to BC, D will be mid point of BC. So coordinates of D = ($$frac{-2+0}{2} ,frac{3-4}{2}$$) = (-1 ,$$frac{-1}{2}$$) Equation of line passing through points A(1,5) and D(-1,$$frac{-1}{2}$$) will be : $$(y-x_{1})=frac{y_{2}-y_{1}}{x_{2}-x_{1}}(x-x_{1})$$ (Here $$(x_{1},y_{1})=(1,5)$$ , $$(x_{2},y_{2})=(-1,frac{-1}{2})$$)
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$$(y-5)=frac{(frac{-1}{2})-(5)}{(-1)-(1)}(x-1)$$
$$4(y-5)=11(x-1)$$
$$11x-4y+9=0$$