1. Ramesh and Sohan start walking away from each other from a point P at an angle of 120°. Ramesh walks at a speed of 3 km/hour while Sohan walks at a speed of 4 km/hour. What is the distance between them after 90 minutes?
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By: anil on 05 May 2019 02.38 am
The distance covered by Ramesh in 90 minutes = 1.5*3 = 4.5 kms Similarly the distance covered by Sohan in 90 minutes = 1.5*4 = 6 kms The distance between Sohan and Ramesh after 90 minutes will be : Cos(A) = $$frac{b^{2}+c^{2}-a^{2}}{2bc}$$ Cos(120) = $$frac{4.5^{2}+6^{2}-d^{2}}{2*4.5*6}$$ $$d^{2}$$ = $$4.5^{2}+6^{2}-2*4.5*6*Cos(120)$$ $$d^{2}$$ = 20.25+36+27 = 83.25 d = $$sqrt{83.25}$$ $$d approx 9.12$$
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