1. If $$10^{67}- 87$$ is written as an integer in base 10 notation, what is the sum of digits in that integer? ·





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  • By: anil on 05 May 2019 02.38 am
    $$10^{67}- 87$$ = $$9999....99913$$ (total 67 digits) Sum of digits =$$65*9 + 1 + 3$$ = 589
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