1. Rakhal is looking for a field where he can graze his cow. He finds a local farmer, Gopal, who agrees to rent hi field to Rakhal for Rs. 1000 a year. Rakhal finds a post in the field and ties his cow to the post with a 25 feet rope. After some months, Gopal tells Rakhal that he will build a shed with four walls on the field with the post as one of the corner posts. The shed would be 15 feet by 10 feet. Rak hal agrees but he realizes that this arrangement would reduce the available area for grazing. What should be the modified rent to compensate for this loss of grazing area if Rakhal has to keep the cow tied to the same post with the same rope?
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By: anil on 05 May 2019 02.37 am
Original area for grazing = $$pi imes (25)^2$$ = $$625 pi$$ sq. feet After the shed (15 $$ imes$$ 10 feet) is built, quarter of the area will be reduced. => New area = $$frac{3}{4} pi imes (25)^2 + frac{1}{4}[pi (10)^2 + pi (15)^2]$$ = $$frac{1875 pi}{4} + frac{325 pi}{4}$$ = $$frac{2200 pi}{4} = 550 pi$$ Now, original area corresponds to Rs. 1,000 => $$625 pi equiv 1000$$ $$ herefore 550 pi equiv 1000 imes frac{550}{625}$$ = $$Rs. 880$$
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