1. In a city, there is a circular park. There are four points of entry into the park, namely - P, Q, R and S. Three paths were constructed which connected the points PQ, RS, and PS. The length of the path PQ is 10 units, and the length of the path RS is 7 units. Later, the municipal corporation extended the paths PQ and RS past Q and R respectively, and they meet at a point T on the main road outside the park. The path from Q to T measures 8 units, and it was found that the angle PTS is 60.
Find the area (in square units) enclosed by the paths PT, TS, and PS.
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By: anil on 05 May 2019 02.37 am
Given : PQ = 10 , QT = 8 , RS = 7 $$angle$$ PTS = 60 To find : $$ar ( riangle PTS) = ?$$ Solution : SU is perpendicular to PT In $$ riangle$$ SUT => $$tan 60 = frac{SU}{QT}$$ => $$sqrt{3} = frac{SU}{8}$$ => $$SU = 8 sqrt{3}$$ $$PT = PQ + QT$$ => $$PT = 10 + 8 = 18$$ $$ herefore ar ( riangle PTS) = frac{1}{2} imes SU imes PT$$ = $$frac{1}{2} imes (8 sqrt{3}) imes 18$$ = $$72 sqrt{3}$$
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