1. A polynomial $$ax^{3} + bx^{2 }+ cx + d$$ intersects x-axis at 1 and -1, and y-axis at 2. The value of b is:
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By: anil on 05 May 2019 02.37 am
Expression : $$ax^{3} + bx^{2 }+ cx + d$$ When it intersects x-axis at x = 1, => Point = (1,0) => $$a(1)^3 + b(1)^2 + c(1) + d = 0$$ => $$a + b + c + d = 0$$ --------Eqn(I) Similarly at (-1,0) => $$a(-1)^3 + b(-1)^2 + c(-1) + d = 0$$ => $$-a + b -c + d = 0$$ => $$(a + c) = (b + d)$$ Substituting it in eqn(I), we get : => $$2 (b + d) = 0$$ => $$b + d = 0$$ ---------Eqn(II) When it intersects y-axis at = 2, => Point = (0,2) => $$a(0)^3 + b(0)^2 + c(0) + d = 2$$ => $$d = 2$$ Substituting it in Eqn(II), => $$b = -2$$
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