1.
Directions for the next 3 questions: For three distinct real positive numbers x, y and z, letf(x, y, z) = min (max(x, y), max (y, z), max (z, x))g(x, y, z) = max (min(x, y), min (y, z), min (z, x))h(x, y, z) = max (max(x, y), max(y, z), max (z, x))j(x, y, z) = min (min (x, y), min(y, z), min (z, x))m(x, y, z) = max (x, y, z)n(x, y, z) = min (x, y, z)Which of the following is necessarily greater than 1?
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By: anil on 05 May 2019 02.30 am
From the given functions we can make out that function h and m give max value , function n and j give min value , function f and g give middle value. From this equation (f(x, y, z) + h(x, y, z)-g(x, y, z))/j(x, y, z) , numerator is always max value and denominator is min value . So this will always be greater than 1 . Suppose x>y>z f(x,y,z) = y g(x,y,z) = y h(x,y,z) = x j(x,y,z) = z Option d = x/z >1
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From the given functions we can make out that function h and m give max value , function n and j give min value , function f and g give middle value. From this equation (f(x, y, z) + h(x, y, z)-g(x, y, z))/j(x, y, z) , numerator is always max value and denominator is min value . So this will always be greater than 1 . Suppose x>y>z f(x,y,z) = y g(x,y,z) = y h(x,y,z) = x j(x,y,z) = z Option d = x/z >1