1.
Ram and Shyam run a race between points A and B, 5 km apart. Ram starts at 9 a.m. from A at a speed of 5 km/hr, reaches B, and returns to A at the same speed. Shyam starts at 9:45 a.m. from A at a speed of 10 km/hr, reaches B and comes back to A at the same speed.At what time do Ram and Shyam first meet each other?
Write Comment
Comments
By: anil on 05 May 2019 02.29 am
Let the time at which they meet be t minutes past 10.
So, distance run by Ram + distance run by Shyam = 10 km
=> (60+t)5/60 [t+60 because he would have traveled for 9 am to 10 am and t minutes more before meeting Shyam]+ (15+t)*10/60 [15+t because he would have traveled from 9:45 to 10:00 and t minutes more]= 10 => 300+5t+150+10t = 600 => t = 10
So, they meet at 10.10 am
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use
So, distance run by Ram + distance run by Shyam = 10 km
=> (60+t)5/60 [t+60 because he would have traveled for 9 am to 10 am and t minutes more before meeting Shyam]+ (15+t)*10/60 [15+t because he would have traveled from 9:45 to 10:00 and t minutes more]= 10 => 300+5t+150+10t = 600 => t = 10
So, they meet at 10.10 am