1. In a tournament, there are n teams $$T_1 , T_2 ....., T_n$$ with $$n > 5$$. Each team consists of k players, $$k > 3$$. The following pairs of teams have one player in common: $$T_1$$ & $$T_2$$ , $$T_2$$ & $$T_3$$ ,......, $$T_{n-1}$$ & $$T_n$$ , and $$T_n$$ & $$T_1$$ . No other pair of teams has any player in common. How many players are participating in the tournament, considering all the n teams together?
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By: anil on 05 May 2019 02.29 am
The number of players in all the teams put together = k * n The number of players that are common is 1*n = n So, the number of players in the tournament = kn - n = n(k-1)
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