1. A parallelogram ABCD has area 48 sqcm. If the length of CD is 8 cm and that of AD is s cm, then which one of the following is necessarily true?





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  • By: anil on 05 May 2019 02.28 am
    We can see that area of parallelogram ABCD = 2*Area of triangle ACD  48 = 2*Area of triangle ACD 
    Area of triangle ACD = 24
    $$(1/2)*CD*DA*sinADC=24$$
    $$AD*sinADC=6$$
    We know that $$sin heta$$ $$leq$$ 1, Hence, we can say that AD $$geq$$ 6 $$Rightarrow$$ s $$geq$$ 6
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