1. The red blood cells in a blood sample grows by 10% per hour in first two hours, decreases by 10% in next one hour, remains constant in next one hour and again increases by 5% per hour in next two hours. If the original count of the red blood cells in the sample is 40000, find the approximate red blood cell count at the end of 6 hours.
Write Comment
Comments
By: anil on 05 May 2019 02.28 am
Original count = 40,000 In the next 2 hours, it increases by 10% => Blood cell count after 2 hours = $$40,000(1+frac{10}{100})^2=40,000(frac{11}{10})^2$$ = $$40,000 imesfrac{121}{100}=48,400$$ It decreases by 10% in next hour => Blood cell count after 3 hours = $$48,400(1-frac{10}{100})^1$$ = $$48,400 imesfrac{9}{10}=43,560$$ It remains constant in the next hour, => Blood cell count after 4 hours = $$43,560$$ In the next 2 hours, it increases by 5% => Blood cell count after 6 hours = $$43,560(1+frac{5}{100})^2=43,560(frac{21}{20})^2$$ = $$43,560 imesfrac{441}{400}=48,024.9approx48,025$$ => Ans - (C)
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use