1. A shopkeeper purchases two items for Rs. 520. One of them is sold gaining 16% and the other at a loss of 10%, thus making no profit or loss. What is the selling price of the item sold at loss ?
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By: anil on 05 May 2019 02.28 am
Let cost price of first item = Rs. $$100x$$ and of second item = Rs. $$(520-100x)$$ Profit % on first item = 16% => Selling price = $$100x+(frac{16}{100} imes100x)=Rs.$$ $$116x$$ Similarly, selling price of item sold at 10% loss = $$(520-100x)-frac{10}{100} imes(520-100x)$$ = $$(520-100x)-52+10x=Rs.$$ $$(468-90x)$$ ------------(i) Since, there is no profit and no loss, hence total cost price = total selling price => $$116x+468-90x=520$$ => $$26x=520-468=52$$ => $$x=frac{52}{26}=2$$ $$ herefore$$ Selling price of the item sold at loss [from equation (i)] = $$468-(90 imes2)$$ = $$468-180=Rs.$$ $$288$$ => Ans - (A)
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