1. The total surface area of a right pyramid on a square base of side 10 cm with height 12 cm is:
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By: anil on 05 May 2019 02.28 am
Height = $$h=12$$ cm and side of base = $$s=10$$ cm => Radius of base = $$r=frac{10}{2}=5$$ cm Perimeter of base = $$4 imes10=40$$ cm Area of base = $$10 imes10=100$$ $$cm^2$$ Thus, slant height = $$l=sqrt{r^2+h^2}$$ => $$l=sqrt{(5)^2+(12)^2}$$ => $$l=sqrt{25+144}=sqrt{169}=13$$ cm Thus, curved surface area of pyramid = $$frac{1}{2} imes$$ Perimeter of base $$ imes$$ slant height = $$frac{1}{2} imes40 imes13=260$$ $$cm^2$$ $$ herefore$$ Total surface area of pyramid = Curved surface area + Area of base = $$260+100=360$$ $$cm^2$$ => Ans - (B)
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