1. If the base of triangle is increased by 10% and height is decreased by 20%, then what will be the percentage change in the area of a triangle?
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By: anil on 05 May 2019 02.27 am
Let the base and height of the triangle be $$10$$ cm Area of triangle = $$frac{1}{2} imes10 imes10=50$$ $$cm^2$$ After increasing the base by 10%, => New base = $$10+(frac{10}{100} imes10)$$ = $$10+1=11$$ cm Similarly, new height = $$10-(frac{20}{100} imes10)$$ = $$10-2=8$$ cm => New area = $$frac{1}{2} imes11 imes8=44$$ $$cm^2$$ $$ herefore$$ Decrease in area = $$frac{(50-44)}{50} imes100=12\%$$ => Ans - (D)
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