1. Walking at speed of 5 km/hr,a man reaches his office 6 minutes late. Walking at 6 km/hr, he reaches there 2 minutes early. The distance of his office is:
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By: anil on 05 May 2019 02.25 am
Let ideal time to reach office is in = $$t$$ hours and let distance = $$d$$ km When he walks at 5 km/hr, he reaches his office 6 minutes late Using, distance = speed $$ imes$$ time => $$d=5(t+frac{6}{60})$$ ---------------(i) Similarly, $$d=6(t-frac{2}{60})$$ ---------------(ii) Comparing equations (i) and (ii), we get : => $$5(t+frac{6}{60})=6(t-frac{2}{60})$$ => $$5t+frac{1}{2}=6t-frac{1}{5}$$ => $$6t-5t=frac{1}{2}+frac{1}{5}$$ => $$t=frac{(5+2)}{10}=frac{7}{10}$$ Substituting it in equation (i), => $$d=5 imes(frac{7}{10}+frac{6}{60})$$ = $$5 imesfrac{48}{60}=frac{48}{12}=4$$ km => Ans - (C)
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