1. A cone of height 12 cm and diameter 10 cm is mounted on a hemisphere of the same diameter. What is the volume of the solid thus formed?





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  • By: anil on 05 May 2019 02.18 am
    Height of cone, $$h$$ = 12 cm and radius of cone, $$r$$ = 5 cm Radius of hemisphere, $$r$$ = 5 cm Volume of solid = Volume of cone + Volume of hemisphere = $$(frac{1}{3} pi r^2 h) + (frac{2}{3} pi r^3)$$ = $$(frac{pi r^2}{3}) [h + 2r]$$ = $$(frac{22 imes 25}{7 imes 3}) (12 + 10)$$ = $$frac{22 imes 22 imes 25}{21} = frac{12100}{21}$$ = $$576.19 cm^2$$
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