1. Find the radius of the circle if the length of its arc is 33 cm whose corresponding central angle is 90° ?





Write Comment

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

  • By: anil on 05 May 2019 02.18 am
    Central angle = $$ heta = 90$$° and  let radius = $$r$$ cm Length of arc = $$frac{ heta}{360} imes 2 pi r = 33$$ => $$frac{90}{360} imes 2 imes frac{22}{7} imes r = 33$$ = $$frac{1}{4} imes 44 imes r = 33 imes 7$$ cm => $$r = frac{33 imes 7}{11} = 21$$ cm => Ans - (A)
Tags
Show Similar Question And Answers
QA->The moon of the planet Saturn on whose surface NASA’sspacecraft Cassini has spotted unexplained arc-shaped, reddish streaks.....
QA->If the angle of intersection of a curve is φ., then deflection angle will be :....
QA->A liquid will not wet the surface of solid if the angle of contact is which angle?....
QA->Which is the planet its length of its day and the tilt of its axis are almost identical to those of the earth?....
QA->If the perimeters is 117cm, find the length of the smallest side?....
MCQ->An arc of 30° in one circle is double an arc in a second circle, the radius of which is three times the radius of the first. Then the angles subtended by the arc of the second circle at its centre is....
MCQ->The area of a circle is proportional to the square of its radius. A small circle of radius 3 cm is drawn within a larger circle of radius 5 cm. Find the ratio of the areaof the annular zone to the area of the larger circle. (Area of the annular zone is the difference between the area of the larger circle and that of the smaller circle). ....
MCQ->Find the radius of the circle if the length of its arc is 33 cm whose corresponding central angle is 90° ?....
MCQ->$$\angle A, \angle B, \angle C$$ are three angles of a triangle. If  $$\angle A - \angle B$$ = $$15^\circ$$, $$\angle B - \angle C$$ = $$30^\circ$$, then $$\angle A$$, $$\angle B$$ and $$\angle C$$ are ....
MCQ->Find length of the arc whose central angle is 90° and radius of the circle is 3.5 cm?....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use
DMCA.com Protection Status Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions