1. $$[\frac{SinA}{(1+CosA)}]+[\frac{(1+CosA)}{SinA}]$$ is equal to
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By: anil on 05 May 2019 03.01 pm
Expression : $$[frac{SinA}{(1+CosA)}]+[frac{(1+CosA)}{SinA}]$$ Taking L.C.M, we get : = $$frac{(sin^2 A) + (1 + cos A)^2}{sin A(1 + cos A)}$$ = $$frac{sin^2 A + cos^2 A + 2cos A + 1}{sin A(1 + cos A)}$$ Using $$(sin^2 A + cos^2 A = 1)$$ = $$frac{2 + 2cos A}{sin A(1 + cos A)} = frac{2(1 + cos A)}{sin A(1 + cos A)}$$ = $$frac{2}{sin A} = 2 cosec A$$
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