1. A solid right circular cone of radius 10 cm and height 8 cm is put inside a cylindrical vessel of radius 11 cm and height 9 cm. How much water in cubic cm will be required to fill the cylindrical vessel completely?
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By: anil on 05 May 2019 02.13 am
Radius of cylinder, R = 11 cm and height, H = 9 cm Radius of cone, r = 10 cm and height, h = 8 cm Water required to fill the cylinder completely = Volume of cylinder - Volume of cone = $$(pi R^2H)-(frac{1}{3} pi r^2h)$$ = $$(pi)(R^2H-frac{1}{3}r^2h)$$ = $$(frac{22}{7})[(11^2 imes 9)-(frac{1}{3} imes 10^2 imes 8)]$$ = $$(frac{22}{7})(1089-frac{800}{3})$$ = $$frac{22}{7} imes frac{2467}{3}$$ $$approx 2584.48$$ $$cm^3$$ => Ans - (B)
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