1. In ΔPQR, S and T are points on side PQ and PR respectively. ST is parallel to QR. If S divides PQ in the ratio 1:5 and length of QR is 15 cm, find ST?
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- By: anil on 05 May 2019 02.12 amST is parallel to QR Let PS = $$x$$ and SQ = $$5x$$ => $$frac{PS}{PQ} = frac{ST}{QR}$$ => $$frac{x}{x + 5x} = frac{ST}{15}$$ => $$frac{1}{6} = frac{ST}{15}$$ => $$ST = frac{15}{6} = 2.5$$ cm
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