1. Two cars travel from city A to city B at a speed of 30 and 36 km/hr respectively. If one car takes 3 hours lesser time than the other car for the journey, then the distance between City A and City B is
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By: anil on 05 May 2019 02.09 am
Let the distance between City A and City B = $$d$$ km Speed of first car = 30 km/hr and speed of second car = 36 km/hr Let time taken by first car = $$t$$ hrs and time taken by second car = $$(t - 3)$$ hrs Using, speed = distance/time for first car : => $$frac{d}{t} = 30$$ => $$d = 30t$$ --------------(i) For second car, => $$frac{d}{t - 3} = 36$$ Substituting value of $$d$$ from equation (i), we get : => $$30t = 36t - 108$$ => $$36t - 30t = 6t = 108$$ => $$t = frac{108}{6} = 18$$ hrs From equation (i), => $$d = 30 imes 18 = 540$$ km => Ans - (D)
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