1. A man moves 24 metres in south direction and turns 90 degrees anticlockwise and moves another 7 metres and takes a right turn and moves 3 metres and then moves 3 metres in the north direction. Find the distance between his initial and his final position.
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By: anil on 05 May 2019 02.09 am
The man moves 24 metres in south direction and turns 90 degrees anticlockwise and moves another 7 metres towards east and takes a right turn and moves 3 metres towards south and then moves 3 metres in the north direction. Thus, distance between initial and final position = $$sqrt{(24)^2+(7)^2}$$ = $$sqrt{576+49}=sqrt{625}=25$$ m => Ans - (A)
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The man moves 24 metres in south direction and turns 90 degrees anticlockwise and moves another 7 metres towards east and takes a right turn and moves 3 metres towards south and then moves 3 metres in the north direction. Thus, distance between initial and final position = $$sqrt{(24)^2+(7)^2}$$ = $$sqrt{576+49}=sqrt{625}=25$$ m => Ans - (A)