1. In ΔABC measure of angle B is 90°. If cosecA = 13/12, and AB = 10cm, then what is the length (in cm) of side AC?
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By: anil on 05 May 2019 02.07 am
Given : AB = 10 cm and cosec A = 13/12 => $$cosecA=frac{AC}{BC}=frac{13}{12}$$ Let $$AC=13x$$ and $$BC=12x$$ In right triangle ABC, => $$(AC)^2=(AB)^2+(BC)^2$$ => $$(13x)^2=(10)^2+(12x)^2$$ => $$169x^2-144x^2=100$$ => $$25x^2=100$$ => $$x^2=frac{100}{25}=4$$ => $$x=sqrt4=2$$ $$ herefore$$ $$AC=13 imes2=26$$ cm => Ans - (D)
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