Sum of all interior angles of regular polygon with $$n$$ sides = $$(n-2) imes180^circ$$ => Sum of interior angles of a regular hexagon = $$(6-2) imes180^circ=720^circ$$ Also, sum of exterior angle of an polygon = $$360^circ$$ $$ herefore$$ Required difference = $$frac{(720-360)}{6}$$ = $$frac{360^circ}{6}=60^circ$$ => Ans - (C)