1. The average of 6 consecutive integers is 15/2. What is the average of last three integers?
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By: anil on 05 May 2019 02.07 am
Let the 6 consecutive integers be = $$(x),$$ $$(x+1),$$ $$(x+2),$$ $$(x+3),$$ $$(x+4)$$ and $$(x+5)$$ Sum of integers = $$(x)+$$ $$(x+1)+$$ $$(x+2)+$$ $$(x+3)+$$ $$(x+4)+$$ $$(x+5)$$ $$=frac{15}{2} imes6$$ => $$6x+15=45$$ => $$6x=45-15=30$$ => $$x=frac{30}{6}=5$$ $$ herefore$$ Average of last three integers = $$frac{(5+3)+(5+4)+(5+5)}{3}$$ = $$frac{27}{3}=9$$ => Ans - (B)
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