1. ΔDEF is right angled at E. If cotD = 5/12, then what is the value of sinF ?
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By: anil on 05 May 2019 02.07 am
Given : $$cot D$$ = $$frac{5}{12}$$ Also, $$cot D=frac{DE}{EF}=frac{5}{12}$$ Let DE = 5 cm and EF = 12 cm Thus, in $$ riangle$$ DEF, => $$(DF)^2=(DE)^2+(EF)^2$$ => $$(DF)^2=(5)^2+(12)^2$$ => $$(DF)^2=25+144=169$$ => $$DF=sqrt{169}=13$$ cm To find : $$sin F=frac{DE}{DF}$$ = $$frac{5}{13}$$ => Ans - (C)
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