1. In ΔABC measure of angle B is 90o. If tanA = 15/8, and AB = 0.8cm, then what is the length (in cm) of side AC?
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By: anil on 05 May 2019 02.06 am
Given : AB = 0.8 cm and tan A = 15/8 To find : AC = ? Solution : In right $$ riangle$$ ABC, => $$tan(A)=frac{BC}{AB}$$ => $$frac{15}{8}=frac{BC}{0.8}$$ => $$BC=frac{15}{8} imes0.8=1.5$$ cm $$ herefore$$ $$(AC)^2=(AB)^2+(BC)^2$$ => $$(AC)^2=(0.8)^2+(1.5)^2$$ => $$(AC)^2=0.64+2.25=2.89$$ => $$AC=sqrt{2.89}=1.7$$ cm => Ans - (A)
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