1. The perimeter and the length of one of the diagonals of a rhombus is 26 cm and 5 cm respectively. Find the length of its other diagonal (in cm).
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By: anil on 05 May 2019 02.04 am
Given : ABCD is a rhombus and perimeter(ABCD) = 26 cm and BD = 5 cm To findĀ : AC = ? SolutionĀ : Diagonals of a rhombus bisect each other at right angle. => BE = $$frac{5}{2}=2.5$$ cm and side of rhombus = AB = $$frac{26}{4}=6.5$$ cm Thus, in right $$ riangle$$ AEB, => $$(AE)^2=(AB)^2-(BE)^2$$ => $$(AE)^2=(6.5)^2-(2.5)^2$$ => $$(AE)^2=42.25-6.25=36$$ => $$AE=sqrt{36}=6$$ cm $$ herefore$$ AC = $$2 imes6=12$$ cm => Ans - (B)
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