1. ΔDEF is right angled at E. If $$cosec D = \frac{5}{4}$$, then what is the value of $$cosec F$$ ?
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By: anil on 05 May 2019 03.00 pm
Given : $$cosec D$$ = $$frac{5}{4}$$ Also, $$cosec D=frac{DF}{EF}=frac{5}{4}$$ Let DF = 5 cm and EF = 4 cm Thus, in $$ riangle$$ DEF, => $$(DE)^2=(DF)^2-(EF)^2$$ => $$(DE)^2=(5)^2-(4)^2$$ => $$(DE)^2=25-16=9$$ => $$DE=sqrt{9}=3$$ cm To find : $$cosec F=frac{DF}{DE}$$ = $$frac{5}{3}$$ => Ans - (A)
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