1. X and Y are two alloys which are prepared by mixing zinc and aluminium in the ratio of 1 : 4 and 11 : 8 respectively. If equal quantities of alloys are melted to form a third alloy Z then what is the ratio of zinc and aluminium in alloy Z ?





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  • By: anil on 05 May 2019 02.04 am
    Ratio of zinc and aluminium in alloy X = 1 : 4 Ratio of zinc and aluminium in alloy Y = 11 : 8
    Let quantity of both alloys taken = L.C.M. (5,9) = 95 units => Zinc in alloy X = $$frac{1}{(1+4)} imes95=19$$ units Aluminium present in alloy X = $$95-19=76$$ units Similarly, zinc in alloy Y = $$55$$ units and aluminium = $$40$$ units $$ herefore$$ Ratio of zinc and aluminium in alloy Z = $$frac{(19+55)}{(76+40)}$$ = $$frac{74}{116}=frac{37}{58}$$ => Ans - (B)
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