1. For the circle shown below, find the length (in cm) of the largest cord of the circle.
Write Comment
Comments
By: anil on 05 May 2019 02.04 am
Given : AT is tangent on the circle. AT = 6 cm and AB = 10 cm To find : Largest chord = Diameter = ? Solution : In right $$ riangle$$ ABT
=> $$(BT)^2=(AB)^2-(AT)^2$$ => $$(BT)^2=(10)^2-(6)^2$$
=> $$(BT)^2=100-36=64$$ => $$BT=sqrt{64}=8$$ cm $$ herefore$$ Diameter = $$2 imes8=16$$ cm => Ans - (C)
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use
=> $$(BT)^2=(AB)^2-(AT)^2$$ => $$(BT)^2=(10)^2-(6)^2$$
=> $$(BT)^2=100-36=64$$ => $$BT=sqrt{64}=8$$ cm $$ herefore$$ Diameter = $$2 imes8=16$$ cm => Ans - (C)