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Multiple Choice Questions
1. If $$a_n=\frac{1}{n+1}+1$$, then find the value of $$a_1+a_3+a_5$$
(A): $$\frac{17}{12}$$
(B): $$\frac{27}{12}$$
(C): $$\frac{37}{12}$$
(D): $$\frac{47}{12}$$
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By: anil on 05 May 2019 03.27 am
Given : $$a_n=frac{1}{n+1}+1$$ To find : $$a_1+a_3+a_5$$ = $$(frac{1}{1+1}+1)+(frac{1}{3+1}+1)+(frac{1}{5+1}+1)$$ = $$(frac{1}{2}+1)+(frac{1}{4}+1)+(frac{1}{6}+1)$$ = $$frac{(6+3+2)}{12}+3$$ = $$frac{11}{12}+3$$ = $$frac{(11+36)}{12}=frac{47}{12}$$ => Ans - (D)
By: anil on 05 May 2019 03.27 am
Given : $$a_n=frac{1}{n+1}+1$$ To find : $$a_1+a_3+a_5$$ = $$(frac{1}{1+1}+1)+(frac{1}{3+1}+1)+(frac{1}{5+1}+1)$$ = $$(frac{1}{2}+1)+(frac{1}{4}+1)+(frac{1}{6}+1)$$ = $$frac{(6+3+2)}{12}+3$$ = $$frac{11}{12}+3$$ = $$frac{(11+36)}{12}=frac{47}{12}$$ => Ans - (D)
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SSC CHSL 17 March 2018 Evening Shift
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