1. Calculate the angle BAC if the angle BIC = $$125^\circ$$ and 'I' be the in-center of the triangle?
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By: anil on 05 May 2019 02.59 pm
Given : $$angle$$ BIC = $$125^circ$$ and I is the incentre of the triangle To find : $$angle$$ BAC Solution : Incentre of a triangle = $$90^circ+frac{1}{2} imes$$ (angle opposite to it) => $$125^circ=90^circ+frac{angle A}{2}$$ => $$frac{angle A}{2}=125^circ-90^circ=35^circ$$ => $$angle A=2 imes35^circ=70^circ$$ => Ans - (C)
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