1. A can complete a piece of work in 18 days, B in 20 days and C in 30 days. B and C together start the work and are forced to leave after 2 days. The time taken by A alone to complete the remaining work is
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By: anil on 05 May 2019 02.01 am
Amount of work done by B and C together in unit time will be $$frac{1}{20}+frac{1}{30}$$=$$frac{5}{60}$$
hence in two days amount of work done by B and C together = $$frac{10}{60}$$
=$$frac{1}{6}$$
remaining work = $$frac{5}{6}$$
A does $$frac{1}{18}$$ amount of work in unit time
hence $$frac{5}{6}$$ amount of work will be done in 15 days.
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hence in two days amount of work done by B and C together = $$frac{10}{60}$$
=$$frac{1}{6}$$
remaining work = $$frac{5}{6}$$
A does $$frac{1}{18}$$ amount of work in unit time
hence $$frac{5}{6}$$ amount of work will be done in 15 days.