1. A trader bought two horses for 19,500. He sold one at a loss of 20% and the other at a profit of 15%. If the selling price of each horse is the same, then their cost prices are respectively.
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By: anil on 05 May 2019 02.00 am
Let CP of one horse = x, then of other = 19500 - x
GIven ,One is sold at loss of 20%, other at 15% gain. SP is same
So, $$frac{80}{100} imes x=frac{115}{100} imes(19500 - x)$$
80x + 115x = 115*19500
x = 115*19500/195
= 11500 Therefore, 19500-x = 8000
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GIven ,One is sold at loss of 20%, other at 15% gain. SP is same
So, $$frac{80}{100} imes x=frac{115}{100} imes(19500 - x)$$
80x + 115x = 115*19500
x = 115*19500/195
= 11500 Therefore, 19500-x = 8000