1. The unit digit in the sum of (124)372 + (124)373 is





Write Comment

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

  • By: anil on 05 May 2019 02.00 am
    Both of numbers have unit digit as 4 and it has a repeating cycle of 2 with unit digits as 4 and 6 
    so in first number power is 372 which is exactly divisible by 2 hence unit digit of first number will be 6.
    and in second number power is 373 which exceeds one with the reapeating cycle of 2 hence its unit digit will be 4. now unit digit of the sum will be 6+4 = 10
Tags
Show Similar Question And Answers
QA->The difference between the largest four digit number and the smallest three digit number is :....
QA->The sum and product of two numbers are 13 and 40 respectively. The sum of their reciprocals is :....
QA->124 people have been killed by floods and mudslides in El Salvador after the Central American nation was battered by a Hurricane. Name of that storm?....
QA->The first digit from the left on PIN code indicates....
QA->The average of the two digit numbers which remains the same when the digits interchange their positions.....
MCQ->The unit digit in the sum of (124)372 + (124)373 is....
MCQ->If N = 196, the result of the following program will be

INTEGER N, DIGIT 1, DIGIT 2, DIGIT 3,
SUM
READ, N
DIGIT 1 = N - (N / 10) 10 N = N / 10
DIGIT 2 = N - (N / 10) 10 N = N / 10
DIGIT 3 = N - (N / 10) 10
SUM = DIGIT 1 + DIGIT 2 + DIGIT 3....
MCQ-> In each question below, a group of digits/symbols is given, followed by four combinations of letters numbered (1), (2), (3), and (4). You have to find out which of the combinations (1), (2), (3) and (4) correctly represents the group of digits/symbols based on the following coding system and the conditions those follow and mark the number of that combination as your answer. If none of the four combinations correctly represents the group of digits/symbols, mark (5) i.e.,’None of these’ as the answer Digit/Symbol 5 9 @ © 3 8 1 $ % 4 2 6 * 7 $$\delta$$ # Letter Code B E P A K D F H Q I R J U M V T Conditions (a) If the first unit in the group is an even digit and the last unit is a symbol, both these are to be coded as the code for the symbol. (b) If the first unit in the group is an odd digit and the last unit is an even digit, their codes are to the unchanged. (c) If both the first and the last units in the group are symbols, both these are to be coded as ‘X’.@91$26
 ....
MCQ->A batch adiabatic reactor at an initial temperature of 373°K is being used for the reaction, A B. Assume the heat of reaction is - 1kJ/mole at 373°K and heat capacity of both A and B to be constant and equal to 50J/mole.K. The temperature rise after a conversion of 0.5 will be....
MCQ-> In these questions a group of digits is given followed by four combinations of letters and symbols numbered a) b) c) d). Digits are to be coded as per the scheme and conditions given below You have to find out which of the four combinations is correct your answer is e) ie None of these. Digit : 5 1 2 8 6 3 9 0 4 7 Letter/Symbol code: H $ T A U % # F R @ Conditions: i.If the first digit is odd and the last digit is even their codes are to be interchanged. ii.If the first as well as the last digit is even both are to be coded as $$\bigstar$$ iii.If the first digit is even and the last digit is odd both are to be coded as the code for the last digit348096
 ....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use
DMCA.com Protection Status Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions