1. Two circles touch each other externally at a point P and a direct common tangent touches the circles at the points Q and R respectively. Then ∠QPR is





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  • By: anil on 05 May 2019 01.58 am
    Since QS and SP are tangents from the same point S => QS = SP => In $$ riangle$$QSP, $$angle$$SQP = QPS
    => $$angle$$SQP + $$angle$$QPS + $$angle$$PSQ = 180° => $$angle$$QPS = 90/2 = 45° Similarly, $$angle$$SPR = 45° Adding above two equations, we get : => $$angle$$QPS + $$angle$$SPR = 45° + 45° => $$angle$$QPR = 90°
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