1. A circular road runs around a circular ground. If the difference between the circumferences of the outer circle and the inner circle is 66 metres, the width of the road is:





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  • By: anil on 05 May 2019 01.57 am
    Let the radius of outer circle be $$R$$ and of smaller circle be $$r$$ Width of road = $$(R - r)$$ = ? Acc to ques : => $$2pi R - 2pi r = 66$$ => $$R - r = frac{33}{pi}$$ => $$R - r = frac{33 * 7}{22} = 10.5 m$$
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