1. A chord AB of a circle C1 of radius (√3 + 1) cm touches a circle C which is concentric to C . If the radius of C is (√3 -1) cm., the length of AB is :





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  • By: anil on 05 May 2019 01.57 am
    OB = $$(sqrt{3} + 1)$$ cm OA = $$(sqrt{3} - 1)$$ cm In right $$ riangle$$ OAB => $$(AB)^2 = (OB)^2 - (OA)^2$$ => $$(AB)^2 = (sqrt{3} + 1)^2 - (sqrt{3} - 1)^2$$ => $$(AB)^2 = (4 + 2sqrt{3}) - (4 - 2sqrt{3})$$ => $$(AB)^2 = 4sqrt{3}$$ => $$AB = sqrt{4sqrt{3}}$$ => $$AB = 2sqrt[4]{3}$$
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