1. If the perimeters of a rectangle and a square are equal and the ratio of two adjacent sides of the rectangle is 1 : 2 then the ratio of area of the rectangle and that of the square is





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  • By: anil on 05 May 2019 01.55 am
    let l, b are the length & breadth of a rectangle, and s be the side of a square.  l:b = 2:1 so l = 2b. given that perimeters of both are same,  2(l+b) = 4s 
    2(2b+b) = 4s 6b = 4s b/s = 2/3 area of rectangle = l*b = 2b*b = 2$$b^{2}$$ area of square = $$s^{2}$$ ratio = (2$$b^{2}$$)/($$s^{2}$$)         = 2$$(b/s)^{2}$$         = 2(4/9) = 8/9 = 8 : 9 so the answer is option D.
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