1. The diagonals AC and BD of a cyclic quadrilateral ABCD intersect each other at the point P. Then, it is always true that





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  • By: anil on 05 May 2019 01.55 am
    As we know that a cyclic quadrilateral can be inscribed into a circle, Hence in triangle APB and in triangle CPD. $$angle PAB = angle PDC$$ (same sector angles)

    $$angle PCD = angle PBA$$ (same sector angles)

    Hence third angle will also be equal and they will be similar triangles.

    So $$frac{AP}{PD} = frac{BP}{PC}$$
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