1. The three equal circles touch each other externally. If the centres of these circles be A, B, C then ABC is
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By: anil on 05 May 2019 01.55 am
Since all the three circles are equal, let radius of each be $$r$$ => AD = DB = $$r$$ => AB = AD + DB = $$2r$$ Similarly, BC = AC = $$2r$$ Since, all sides are equal, => ABC is an equilateral triangle.
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