1. $$55^{3} + 17^{3} - 72^{3}$$ + 201960 is equal to





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  • By: anil on 05 May 2019 01.55 am
    $$55^{3} + 17^{3} - 72^{3}$$ + 201960 we know that $$a^3 + b^3 + c^3 - 3 a b c$$ = 0 ,if a+b+c = 0 here , the equation $$55^{3} + 17^{3} - 72^{3}$$ + 201960 = $$55^{3} + 17^{3} + (-72)^{3} - 3 imes 55 imes 17 imes (-72)$$ a = 55 , b = 17 , c = -72 55+17+(-72) = 0 hence , $$55^{3} + 17^{3} - 72^{3}$$ + 201960 = 0
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