1. You arrive at your school 5 minutes late if you walk with a speed of 4 km/h, but you arrive 10 minutes before the scheduled time if you walk with a speed of 5 km/h. The distance of your school from your house (in km) is
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By: anil on 05 May 2019 01.54 am
Here the distance between home and school will remain same , let the distance be D Let the original time taken be T hours as in both cases the distance remain constant, we can use $$frac{S1}{S2}$$ = $$frac{T2}{T1}$$ T1 = T + $$frac{1}{12}$$ hr , S1 = 4 km/hr T2 = T - $$frac{1}{6}$$ hr , S2 = 5 km/hr So, $$frac{4}{5}$$ = $$frac{(T-frac{1}{6})}{(T+frac{1}{12})}$$ T = $$frac{7}{6}$$ hour Distance = Speed x Time Distance of School = 4 x $$frac{15}{12}$$ = 5 km
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