1. Two cubes have their volumes in the ratio 27 : 64. The ratio of their surface areas is
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By: anil on 05 May 2019 01.54 am
let the side of 1st cube and 2nd cube be a unit and b unit respectively now volume of a cube = $$side^3$$ total surface area of cube = 6$$side^2$$ given that : $$frac{a^3}{b^3} = frac{27}{64}$$ $$frac{a}{b} = frac{3}{4}$$ Now we can say that $$frac{6a^2}{6b^2} = frac{9}{16}$$
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