1. O is the circumcentre of ΔABC, given ∠BAC = 85° and ∠BCA = 55°, find ∠OAC.






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  • By: anil on 05 May 2019 01.54 am
    Since $$angle$$BAC = 85°
    => $$angle$$BOC = 2 * 85 = 170° Similarly, $$angle$$AOB = 2 * $$angle$$BCA = 2*55 = 110° => $$angle$$AOC = 360° - 170° - 110° = 80° Since, OA & OC are radii, => OA = OC, => $$angle$$OAC = $$angle$$OCA In $$ riangle$$AOC => $$angle$$OAC = $$angle$$OCA = $$frac{1}{2}(180^{circ} - 80^{circ})$$ = $$frac{100}{2} = 50^{circ}$$
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