1. In the given figure, POQ is a diameter and PQRS is a cyclic quadrilateral. If ∠PSR = 130°, then the value of ∠RPQ is
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By: anil on 05 May 2019 01.53 am
As we know that it is a cyclic quadrilateral , then all points P, Q R ,S are on circumferene of ceircle we know sum of opposite angles in cyclic quad. = 180 Hence , ∠P + ∠R = 180 ∠S + ∠Q = 180
∠S = 130 , so ∠Q = 50
If PQ is a diameter , then ∠PRQ = 90 Sum of angles in a traingle = 180 Hence ∠RPQ = 180 - (90+50) = 40
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∠S = 130 , so ∠Q = 50
If PQ is a diameter , then ∠PRQ = 90 Sum of angles in a traingle = 180 Hence ∠RPQ = 180 - (90+50) = 40