1. If $$2x+3y=\frac{5}{6} and $$xy=\frac{5}{6}$$ then the value of $$8x^{3}+27y^{3}$$ is
Write Comment
Comments
By: anil on 05 May 2019 02.57 pm
$$2x+3y=frac{11}{2}$$ cubing on both sides $$(2x+3y)^{3}=(frac{11}{2})^{3}$$
$$8x^{3}+27y^{3}+3(2x)(8y)(2x+3y)=frac{1331}{8}$$
$$8x^{3}+27y^{3}+3(16xy)(2x+3y)=frac{1331}{8}$$
$$8x^{3}+27y^{3}+3(16(frac{5}{6})(frac{5}{6})=frac{1331}{8}$$
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use
$$8x^{3}+27y^{3}+3(2x)(8y)(2x+3y)=frac{1331}{8}$$
$$8x^{3}+27y^{3}+3(16xy)(2x+3y)=frac{1331}{8}$$
$$8x^{3}+27y^{3}+3(16(frac{5}{6})(frac{5}{6})=frac{1331}{8}$$