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1. In ΔABC, if AD ⊥ BC, then $$AB^{2} + CD^{2}$$ is equal
(A): $$2 BD^{2}$$
(B): $$BD^{2}+ AC^{2}$$
(C): $$2 AC^{2}$$ 75°
(D): None of these 15°
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By: anil on 05 May 2019 01.53 am
According to perpendicular bisector theorem $$AB^{2} + CD^{2}$$= $$BD^{2}+ AC^{2}$$ (B)
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SSC CGL 2014 Tier 1 26 Oct shift 3
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