1. In ΔABC, if AD ⊥ BC, then $$AB^{2} + CD^{2}$$ is equal





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  • By: anil on 05 May 2019 01.53 am
    According to perpendicular bisector theorem $$AB^{2} + CD^{2}$$= $$BD^{2}+ AC^{2}$$ (B)
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